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Future Smoker is Finished

Started by classicrockgriller, June 27, 2010, 02:35:11 PM

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classicrockgriller

I either need to get this running or find someone that wants a nice Cabinet for a Smoker.

http://forum.bradleysmoker.com/index.php?topic=14749.0

I had this from a project I didn't do.



I had it plugged into a 25 foot extention cord.



I took various reading from 3 different rack levels.

This is from the middle of the smoker.





Rack 10" above middle





10 " below middle rack






classicrockgriller

I'll plug up the element that came with it tomorrow and take some more readings.

squirtthecat


Looks like it'll be plenty powerful enough..

Get yourself another PID (or even a Ranco) to reign that sucker in.

hal4uk

That thing oughtta do some serious smokin!
No Swine Left Behind KCBS BBQ Team
Peoria Custom Cookers "Meat Monster"
Lang Clone - 'Blue October'
Original Bradley Smoker
MAK 1 Star General
Traeger Lil' Tex
Backwoods Chubby

classicrockgriller

That Cabinet was still holding 150* 2 1/2 hrs after I shut everything down.

I'm thinking I really don't need to go to a 220 element.

Maybe Mr Walleye or HawkeyeSmokes will read this and tell me what they think.

hal4uk

That cab looks like it is probably very well insulated, so it seems like - once it's up to temp, it wouldn't require much at all to keep it there..
No Swine Left Behind KCBS BBQ Team
Peoria Custom Cookers "Meat Monster"
Lang Clone - 'Blue October'
Original Bradley Smoker
MAK 1 Star General
Traeger Lil' Tex
Backwoods Chubby

classicrockgriller

I know it was empty when I did this, but it got to temp in less than a hour.

Also when I opened the door to move the probes around the temp had stablelized

in 15 to 20 minutes each time.

HawkeyeSmokes

Hey Sonny, glad see to see you fired this up and started to have some fun with it.

Your first run looks good.

I would mount your SG in it and add a top vent to it and test again. That will give you an idea of how it heats up with some air flow through it. Put a drip pan over the heating element to for the test.

You might have enough heat with the 1500W element for the smoking plans you have for it.

Keep us posted.

;D ;D



HawkeyeSmokes

classicrockgriller

Quote from: HawkeyeSmokes on June 27, 2010, 06:23:24 PM
Hey Sonny, glad see to see you fired this up and started to have some fun with it.

Your first run looks good.

I would mount your SG in it and add a top vent to it and test again. That will give you an idea of how it heats up with some air flow through it. Put a drip pan over the heating element to for the test.

You might have enough heat with the 1500W element for the smoking plans you have for it.

Keep us posted.

;D ;D





Thanks HES.

classicrockgriller

I wired up the element that came with the F S #3.

Again I used the same extention cord and just let the probe rest right below the top shelf from yesterday.

I didn't move the probe around.

30 mins -> 201*

45 mins -> 245*

1 hr -> 258*

it maxed out at the 1 hr 20 min mark at 280*

I opened the door and let the maverick reach 200 and shut the door back.

it went from 200 to 250 in 2 1/2 minutes.

reached 269 at the 5 minute mark

and maxed back out at 280* at the 9 minute mark.

I unplugged everything and at 15 minutes had a reading of 241*

30 minutes 215*

1 hr 180*

1 1/2 hr 158*

2 hrs 145*

classicrockgriller

Based on the watt to amp calculator:

1500 watt element at 120 volts draws 12.5 amps.

The unknown is the original element.

If it is a 1000 watt element, 8.33 amps

If it is a 1250 watt element, 10.4 amps

Kinda thinking of leaving the element that is there (it is mounted on the side wall)

and letting it free run on it's own circuit.

Putting the 1500 watt element on a PID with the smoke generator and controlling that element for high heat smoke/cooks

and not turn on the side element for low heat smoke/cooks.

Is there a test (ohms?) to determend the watts of the side element?

KevinG

P=VI
V=IR, so I = V/R
Measure the resistance
Divide the voltage by the resistance to get the current
Multiply the current times the voltage and you'll get the power.
Rodney Dangerfield got his material from watching me.
Learn to hunt deer www.lulu.com/mediabyKevinG

classicrockgriller

Quote from: KevinG on June 28, 2010, 01:01:26 PM
P=VI
V=IR, so I = V/R
Measure the resistance
Divide the voltage by the resistance to get the current
Multiply the current times the voltage and you'll get the power.


Kevin, I only speak english. ;D

KevinG

lol

(120 / Resistance) X 120 = power
Rodney Dangerfield got his material from watching me.
Learn to hunt deer www.lulu.com/mediabyKevinG

classicrockgriller

#14
ok I know i have a 1250 watt element.

I O'ed out the metter.

I tested it and it read .6  (between 0 and 1) on x10 scale.